D. Bessel function norm (Neumann)

To compute the norm of the solution of the equation for the geometry, we need to compute the norm of the Bessel function, which is defined as follows

0μrJm2(r)dr,\int_0^{\mu} r \cdot J_m^2(r) \,dr,
(D.1)

where μ\mu is one of the solutions of the equation dJm(r)drr=μ\frac{\displaystyle d J_m(r)}{\displaystyle dr} \bigg|_{r=\mu} =0= 0.

From formula (C.4) for rr =μ= \mu, where Jm(μ)J_m'(\mu) =0= 0, we obtain the relation mJm(μ)m \cdot J_m(\mu) =μJm+1(μ)= \mu \cdot J_{m+1}(\mu), which is used below.

Let us try to compute the norm (D.1) by integration by parts:

0μrJm2(r)dr\displaystyle \int_0^{\mu} r \cdot J_m^2(r) \,dr =u=rmJm(r),v=rm+1Jm+1(r)du=mrm1Jm(r)dr+rm1[mJm(r)rJm+1(r)]drdv=rm+1Jm(r)dr\displaystyle = \left | \begin{array}{l} u = r^{-m} \cdot J_m(r), \quad v = r^{m+1} \cdot J_{m+1}(r)\\ du = -m \cdot r^{-m-1} \cdot J_m(r) \,dr + r^{-m-1} \cdot \left[ m \cdot J_m(r) - r \cdot J_{m+1}(r) \right] \,dr\\ dv = r^{m+1} \cdot J_m(r) \,dr \end{array} \right |

The boundary term, unlike the Dirichlet case, does not vanish:

rJm(r)Jm+1(r)0μ\displaystyle r \cdot J_m(r) \cdot J_{m+1}(r) \bigg|_0^{\mu} =μJm(μ)Jm+1(μ)\displaystyle = \mu \cdot J_m(\mu) \cdot J_{m+1}(\mu) =mJm2(μ).\displaystyle = m \cdot J_m^2(\mu).
0μrJm2(r)dr\displaystyle \int_0^{\mu} r \cdot J_m^2(r) \,dr =mJm2(μ)\displaystyle = m \cdot J_m^2(\mu) +0μrJm+12(r)dr.\displaystyle + \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr.

We integrate the resulting integral by parts as well:

0μrJm+12(r)dr\displaystyle \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr =u=Jm+12(r),du=2Jm+1(r)1r[(m+1)Jm+1(r)+rJm(r)]drdv=rdr,v=r2/2\displaystyle = \left | \begin{array}{ll} u = J_{m+1}^2(r), &du = 2 \cdot J_{m+1}(r) \cdot \frac{\displaystyle 1}{\displaystyle r} \cdot \left[ - (m+1) \cdot J_{m+1}(r) + r \cdot J_m(r) \right] \,dr\\ dv = r \,dr, &v = r^2 / 2 \end{array} \right |
0μrJm+12(r)dr\displaystyle \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr =m22Jm2(μ)\displaystyle = \frac{\displaystyle m^2}{\displaystyle 2} \cdot J_m^2(\mu) +(m+1)0μrJm+12(r)dr\displaystyle + (m+1) \cdot \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr 0μr2Jm(r)Jm+1(r)dr.\displaystyle - \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr.

We integrate the last integral by parts:

0μr2Jm(r)Jm+1(r)dr\displaystyle \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr =u=rm+2Jm(r),v=rmJm(r)du=(m+2)rm+1Jm(r)+rm+1[mJm(r)rJm+1(r)]drdv=rmJm+1(r)dr\displaystyle = \left | \begin{array}{l} u = r^{m+2} \cdot J_m(r), \quad v = - r^{-m} \cdot J_m(r)\\ du = (m+2) \cdot r^{m+1} \cdot J_m(r) + r^{m+1} \cdot \left[ m \cdot J_m(r) - r \cdot J_{m+1}(r) \right] \,dr\\ dv = r^{-m} \cdot J_{m+1}(r) \,dr \end{array} \right |
uv0μ\displaystyle u \cdot v \bigg|_0^{\mu} =r2Jm2(r)0μ\displaystyle = - r^2 \cdot J_m^2(r) \bigg|_0^{\mu} =μ2Jm2(μ),\displaystyle = - \mu^2 \cdot J_m^2(\mu),
duv\displaystyle du \cdot v =2(m+1)rJm2(r)\displaystyle = - 2 \cdot (m+1) \cdot r \cdot J_m^2(r) +r2Jm(r)Jm+1(r),\displaystyle + r^2 \cdot J_m(r) \cdot J_{m+1}(r),
0μr2Jm(r)Jm+1(r)dr\displaystyle \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr =μ2Jm2(μ)\displaystyle = - \mu^2 \cdot J_m^2(\mu) +2(m+1)0μrJm2(r)dr\displaystyle + 2 \cdot (m+1) \cdot \int_0^{\mu} r \cdot J_m^2(r) \,dr 0μr2Jm(r)Jm+1(r)dr,\displaystyle - \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr,
0μr2Jm(r)Jm+1(r)dr\displaystyle \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr =μ22Jm2(μ)\displaystyle = - \frac{\displaystyle \mu^2}{\displaystyle 2} \cdot J_m^2(\mu) +(m+1)0μrJm2(r)dr.\displaystyle + (m+1) \cdot \int_0^{\mu} r \cdot J_m^2(r) \,dr.

Substituting the obtained equalities successively into one another, we express the norm:

0μrJm+12(r)dr\displaystyle \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr =1m0μr2Jm(r)Jm+1(r)dr\displaystyle = \frac{\displaystyle 1}{\displaystyle m} \cdot \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr m2Jm2(μ),\displaystyle - \frac{\displaystyle m}{\displaystyle 2} \cdot J_m^2(\mu),
0μrJm2(r)dr\displaystyle \int_0^{\mu} r \cdot J_m^2(r) \,dr =mJm2(μ)\displaystyle = m \cdot J_m^2(\mu) +1m0μr2Jm(r)Jm+1(r)dr\displaystyle + \frac{\displaystyle 1}{\displaystyle m} \cdot \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr m2Jm2(μ),\displaystyle - \frac{\displaystyle m}{\displaystyle 2} \cdot J_m^2(\mu),
0μrJm2(r)dr\displaystyle \int_0^{\mu} r \cdot J_m^2(r) \,dr =m2Jm2(μ)\displaystyle = \frac{\displaystyle m}{\displaystyle 2} \cdot J_m^2(\mu) +1m0μr2Jm(r)Jm+1(r)dr,\displaystyle + \frac{\displaystyle 1}{\displaystyle m} \cdot \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr,
0μrJm2(r)dr\displaystyle \int_0^{\mu} r \cdot J_m^2(r) \,dr =m2Jm2(μ)\displaystyle = \frac{\displaystyle m}{\displaystyle 2} \cdot J_m^2(\mu) μ22mJm2(μ)\displaystyle - \frac{\displaystyle \mu^2}{\displaystyle 2 \cdot m} \cdot J_m^2(\mu) +m+1m0μrJm2(r)dr,\displaystyle + \frac{\displaystyle m+1}{\displaystyle m} \cdot \int_0^{\mu} r \cdot J_m^2(r) \,dr,
1m0μrJm2(r)dr\displaystyle \frac{\displaystyle 1}{\displaystyle m} \cdot \int_0^{\mu} r \cdot J_m^2(r) \,dr =m2Jm2(μ)\displaystyle = - \frac{\displaystyle m}{\displaystyle 2} \cdot J_m^2(\mu) +μ22mJm2(μ).\displaystyle + \frac{\displaystyle \mu^2}{\displaystyle 2 \cdot m} \cdot J_m^2(\mu).

Finally we obtain:

0μrJm2(r)dr\displaystyle \int_0^{\mu} r \cdot J_m^2(r) \,dr =(μ2m2)Jm2(μ)2.\displaystyle = \left( \mu^2 - m^2 \right) \cdot \frac{\displaystyle J_m^2(\mu)}{\displaystyle 2}.
(D.2)