C. Bessel function norm (Dirichlet)

To compute the norm of the solution of the equation for the geometry, we need to compute the norm of the Bessel function, which is defined as follows

0μrJm2(r)dr,\int_0^{\mu} r \cdot J_m^2(r) \,dr,
(C.1)

where μ\mu is one of the solutions of the equation Jm(μ)J_m(\mu) =0= 0.

The following integrals are known

rm+1Jm(r)dr\displaystyle \int r^{m+1} \cdot J_m(r) \,dr =rm+1Jm+1(r)\displaystyle = r^{m+1} \cdot J_{m+1}(r) +C,\displaystyle + C,
(C.2)
rmJm+1(r)dr\displaystyle \int r^{-m} \cdot J_{m+1}(r) \,dr =rmJm(r)\displaystyle = - r^{-m} \cdot J_m(r) +C,\displaystyle + C,
(C.3)

as well as the formulas for the derivatives of the Bessel function

rdJm(r)dr\displaystyle r \cdot \frac{\displaystyle d J_m(r)}{\displaystyle dr} =mJm(r)\displaystyle = m \cdot J_m(r) rJm+1(r),as m\displaystyle - r \cdot J_{m+1}(r), \quad \text{as } m =0  \displaystyle = 0 \;   dJ0(r)dr\displaystyle \Rightarrow\; \frac{\displaystyle d J_0(r)}{\displaystyle dr} =J1(r),\displaystyle = - J_1(r),
(C.4)
rdJm(r)dr\displaystyle r \cdot \frac{\displaystyle d J_m(r)}{\displaystyle dr} =mJm(r)\displaystyle = - m \cdot J_m(r) +rJm1(r),as m\displaystyle + r \cdot J_{m-1}(r), \quad \text{as } m =0  \displaystyle = 0 \;   dJ0(r)dr\displaystyle \Rightarrow\; \frac{\displaystyle d J_0(r)}{\displaystyle dr} =J1(r).\displaystyle = J_{-1}(r).
(C.5)

Let us try to compute the norm (C.1) by integration by parts:

0μrJm2(r)dr\displaystyle \int_0^{\mu} r \cdot J_m^2(r) \,dr =u=rmJm(r),v=rm+1Jm+1(r)du=mrm1Jm(r)dr+rm1[mJm(r)rJm+1(r)]drdv=rm+1Jm(r)dr\displaystyle = \left | \begin{array}{l} u = r^{-m} \cdot J_m(r), \quad v = r^{m+1} \cdot J_{m+1}(r)\\ du = -m \cdot r^{-m-1} \cdot J_m(r) \,dr + r^{-m-1} \cdot \left[ m \cdot J_m(r) - r \cdot J_{m+1}(r) \right] \,dr\\ dv = r^{m+1} \cdot J_m(r) \,dr \end{array} \right |
0μrJm2(r)dr\displaystyle \int_0^{\mu} r \cdot J_m^2(r) \,dr =rJm(r)Jm+1(r)0μ\displaystyle = r \cdot J_m(r) \cdot J_{m+1}(r) \bigg|_0^{\mu} +0μrJm+12(r)dr\displaystyle + \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr =0μrJm+12(r)dr.\displaystyle = \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr.

We integrate the resulting integral by parts as well:

0μrJm+12(r)dr\displaystyle \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr =u=Jm+12(r),du=2Jm+1(r)1r[(m+1)Jm+1(r)+rJm(r)]drdv=rdr,v=r2/2\displaystyle = \left | \begin{array}{ll} u = J_{m+1}^2(r), &du = 2 \cdot J_{m+1}(r) \cdot \frac{\displaystyle 1}{\displaystyle r} \cdot \left[ - (m+1) \cdot J_{m+1}(r) + r \cdot J_m(r) \right] \,dr\\ dv = r \,dr, &v = r^2 / 2 \end{array} \right |
0μrJm+12(r)dr\displaystyle \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr =μ22Jm+12(μ)\displaystyle = \frac{\displaystyle \mu^2}{\displaystyle 2} \cdot J_{m+1}^2(\mu) +(m+1)0μrJm+12(r)dr\displaystyle + (m+1) \cdot \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr 0μr2Jm(r)Jm+1(r)dr.\displaystyle - \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr.

We integrate the last integral by parts:

0μr2Jm(r)Jm+1(r)dr\displaystyle \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr =u=rm+2Jm(r),v=rmJm(r)du=(m+2)rm+1Jm(r)+rm+1[mJm(r)rJm+1(r)]drdv=rmJm+1(r)dr\displaystyle = \left | \begin{array}{l} u = r^{m+2} \cdot J_m(r), \quad v = - r^{-m} \cdot J_m(r)\\ du = (m+2) \cdot r^{m+1} \cdot J_m(r) + r^{m+1} \cdot \left[ m \cdot J_m(r) - r \cdot J_{m+1}(r) \right] \,dr\\ dv = r^{-m} \cdot J_{m+1}(r) \,dr \end{array} \right |
uv0μ\displaystyle u \cdot v \bigg|_0^{\mu} =r2Jm2(r)0μ\displaystyle = - r^2 \cdot J_m^2(r) \bigg|_0^{\mu} =0,\displaystyle = 0,
duv\displaystyle du \cdot v =2(m+1)rJm2(r)\displaystyle = - 2 \cdot (m+1) \cdot r \cdot J_m^2(r) +r2Jm(r)Jm+1(r),\displaystyle + r^2 \cdot J_m(r) \cdot J_{m+1}(r),
0μr2Jm(r)Jm+1(r)dr\displaystyle \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr =2(m+1)0μrJm2(r)dr\displaystyle = 2 \cdot (m+1) \cdot \int_0^{\mu} r \cdot J_m^2(r) \,dr 0μr2Jm(r)Jm+1(r)dr,\displaystyle - \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr,
0μr2Jm(r)Jm+1(r)dr\displaystyle \int_0^{\mu} r^2 \cdot J_m(r) \cdot J_{m+1}(r) \,dr =(m+1)0μrJm2(r)dr.\displaystyle = (m+1) \cdot \int_0^{\mu} r \cdot J_m^2(r) \,dr.

Let us substitute the last equality into the previously obtained expression for the integral 0μrJm+12(r)dr\int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr. Taking into account the equality 0μrJm2(r)dr\int_0^{\mu} r \cdot J_m^2(r) \,dr =0μrJm+12(r)dr= \int_0^{\mu} r \cdot J_{m+1}^2(r) \,dr, the terms with (m+1)(m+1) cancel, and we finally obtain:

0μrJm2(r)dr\displaystyle \int_0^{\mu} r \cdot J_m^2(r) \,dr =μ22Jm+12(μ).\displaystyle = \frac{\displaystyle \mu^2}{\displaystyle 2} \cdot J_{m+1}^2(\mu).
(C.6)